Graph#

New Post: Positioning new vertex from beginning

dmartel — Thu, 16 Feb 2012 11:29:16 GMT

Hi guys, i am not an expert, i just have been working with graph# for a while. I am going to explain what works for me.

If you want to set de position of a vertex at the moment that is loaded, you just need to do it on Loaded event, i will show in code.

private void vertex_Loaded(object sender, RoutedEventArgs e)
{
            VertexControl aux = new VertexControl();
            aux = ((VertexControl)sender);

            double posx, posy;

            posx = "x position of vertex";
            posy = "y position of vertex";

            GraphCanvas.SetX(aux, posx);
            GraphCanvas.SetY(aux, posy);
                                                  
            e.Handled = true;
}

I hope it helps.

New Post: How do I get started?

gabrielpaulsson — Wed, 15 Feb 2012 14:22:24 GMT

I started my testproject and included the GRaphSharp, GRaphsharp.Controls, QuickGRaph and WPFextensions.

When I declare the xmlns:graphsharp="clr-namespace:GraphSharp.Controls;assembly=GraphSharp.Controls" part into my xaml it compiles but will generate problem loading on my XAML viewer.

My error message tells me following:

Error 1 Unable to load the metadata for assembly 'GraphSharp.Controls'. This assembly may have been downloaded from the web. See http://go.microsoft.com/fwlink/?LinkId=179545. The following error was encountered during load: Could not load file or assembly 'GraphSharp.Controls, Version=1.0.3438.42202, Culture=neutral, PublicKeyToken=null' or one of its dependencies. Operation is not supported. (Exception from HRESULT: 0x80131515) c:\users\gabriel\documents\visual studio 2010\Projects\GraphSharp\GraphSharp\MainWindow.xaml 1 1 GraphSharpTest

Any suggestions?

New Post: Graph# in a UserControl

labberlich — Thu, 09 Feb 2012 16:29:23 GMT

Hi all!

I have a problem wirh Graph' in a UserControl.

Is it not possible to set a LayoutAlgorithmType like "Tree" in an User Control?

Everytime when I run my project, are the verticles arranged one above the other. The LayoutAlgorithmType was not applied.

Does anyone know something about it?

New Post: Connect two Vertex with Mouse Action

labberlich — Thu, 09 Feb 2012 15:35:51 GMT

Okay by changing the dll I get my result...

New Post: Connect two Vertex with Mouse Action

labberlich — Wed, 08 Feb 2012 09:12:59 GMT

Maybe I receive an answer if I change my question?

I can drag&drop my verticles arround but my problem is, the vertex thinks he is still selected.

So the effect: when I drag&drop a vertex somewhere and my mousepointer goes over the dragged vertex I can still move it without any MouseDown.

This ist not nice. Please can anyone help?

New Post: Connect two Vertex with Mouse Action

labberlich — Tue, 07 Feb 2012 15:11:06 GMT

Okay I realized it by using Drag&Drop :)

But now I have the problem of moving Verticles.

If I drag a vertex it comes with my mouse pointer.

How can I set a vertex to fix, so that it cannot move?

New Post: Connect two Vertex with Mouse Action

labberlich — Mon, 06 Feb 2012 17:46:13 GMT

Hi all,

does anyone know if it is possilbe to connect two vertex with mouse event?

Maybe with Drag&Drop oder with a menuitem in contextmenu?

Is there an event?

Thank you for your help!

New Post: Fixing the position of nodes in layouts

dlev — Sun, 05 Feb 2012 10:04:31 GMT

Hello,

I would like to fix the position of two nodes and then have the layout algorithm figure out the positions of the other nodes. Does anyone have a suggestion of the best way to do this?

--DLev

New Post: how to reduce drag drop sensitivity

dmartel — Thu, 02 Feb 2012 08:32:59 GMT

Something new about this topic?

Thanks

New Post: The given key was not present in the dictionary

rababk — Sun, 29 Jan 2012 12:17:01 GMT

I solved it, all i had to do is:

graphLayout.Children.Clear();

before I do changes on the graph

New Post: Changing Vertex color of a single node

palesz — Sun, 29 Jan 2012 11:46:19 GMT

I think you're missing the actual DataTemplate in this code:

<DataTemplate DataType="{x:Type Sample:MSVertex}">
        <DataTemplate.Triggers>
        	<DataTrigger Binding="{Binding Path=Status}" Value="1">
                    <Setter TargetName="vertexBorder" Property="Backgroundcolor" Value="blue"></Setter>
                </DataTrigger>
	</DataTemplate.Triggers>
</DataTemplate>

See badang's example (it's the 5th message above your one), the releveant part (you're missing the emphasised border part):

<Border x:Name="vertexBorder">

<StackPanel ToolTip="{Binding Path=Description}" x:Name="vertexPanel">

<TextBlock />

</StackPanel>

</Border>

<DataTemplate.Triggers>

</DataTrigger>

</DataTemplate.Triggers>

</DataTemplate>

ps: @labberlich: Your problem has nothing to do with Graph#. If WPF is new for you, then you should start learning WPF (datatemplates, triggers, XAML, ...) - and ask those questions on a WPF forum.

New Post: Changing Vertex color of a single node

labberlich — Sun, 29 Jan 2012 11:35:28 GMT

Hi Guys,

I have a question to this solution:

In case of a property of my new class MSVertex I want to change the color (background and border) of a Vertex.

Therefor I wrote this code:

<DataTemplate DataType="{x:Type Sample:MSVertex}">
        <DataTemplate.Triggers>
        	<DataTrigger Binding="{Binding Path=Status}" Value="1">
                    <Setter TargetName="vertexBorder" Property="Backgroundcolor" Value="blue"></Setter>
                </DataTrigger>
	</DataTemplate.Triggers>
</DataTemplate>

Now if I try to run the code, I get the Error: Cannot find the Trigger.Destination "vertexBorder"

So how can I define the TargetName or which is the right target name?

Can anyone help me?

New Post: The given key was not present in the dictionary

rababk — Sun, 29 Jan 2012 07:56:46 GMT

I get this message a while after removing the existing graph and displaying the new graph, not while removing... any idea?

New Post: Programmatically change selected edge color

fantaman80 — Thu, 26 Jan 2012 21:09:14 GMT

Find it!

Probably it can be done by xaml code, but i don't know WPF very well; so i found a solution via c# code.

If for example e1 is the variable that contain edge to modify color, and Acqua is the color you want..:

EdgeControl ec1 = graphLayout.GetEdgeControl(e1);
Brush pp1 = new SolidColorBrush(Colors.Aqua);
ec1.Foreground = pp1;

New Post: The given key was not present in the dictionary

fantaman80 — Thu, 26 Jan 2012 15:24:57 GMT

I had this message when i try to remove a not existing vertex or edge in my graph.

When did this message appear?

New Post: The given key was not present in the dictionary

rababk — Thu, 26 Jan 2012 10:14:57 GMT

I get this inner exception when I make changes on the graph, here is the stack trace:

at System.Collections.Generic.Dictionary`2.get_Item(TKey key)

at QuickGraph.BidirectionalGraph`2.ContainsEdge(TEdge edge)

at GraphSharp.Controls.GraphLayout`3.HighlightTriggerEventHandler(Object sender, HighlightTriggeredEventArgs args)

How can I get passed this problem?

New Post: Programmatically change selected edge color

Fantaman80 — Fri, 20 Jan 2012 15:27:11 GMT

Hi all,

i found these method "graphLayout.HighlightEdge(Edge<object, object> edge, Object highlightInfo)" and "graphLayout.RemoveHighlightFromEdge(Edge<object, object> edge)" to change selected edge color, and it works.

But the colors I want are different from Black and Silver that these methods produce. So i ask is possible to change these colors?

Or are there another functions to call or xaml to write to programmatically change the color of an edge?

Thanks.

New Post: Click event On Vertex

aditya_kanekar — Wed, 18 Jan 2012 09:31:50 GMT

You can use MouseDown event available on the EdgeControl as follows,

 <Style TargetType="{x:Type graphsharp:EdgeControl}">
            <EventSetter Event="MouseDown"
                         Handler="Delete_Edge" />
 </Style>

New Post: Tree layout direction & adding controls to the graph

essamosallam — Tue, 17 Jan 2012 14:42:13 GMT

Hi ,

1-i'm trying to change the direction of the layout (layout algorithm parameter-layout direction) for

the tree to be LeftToRight (by default its shown TopToBottom) but i couldn't find the attribute

or the property to do so.

Xaml:

        <zoom:ZoomControl DockPanel.Dock="Bottom" Name="Zoom"  Zoom="0.2"
								ZoomBoxOpacity="0.5" Background="White" Margin="-2,8,2,-8">
            <tree:PocGraphLayout 
									DestructionTransition="{x:Null}"
									IsAnimationEnabled="False"
									x:Name="graphLayout" Margin="10"
									Graph="{Binding Path=Graph}"
									OverlapRemovalAlgorithmType="FSA"
                                    					LayoutAlgorithmType="Tree"
									HighlightAlgorithmType="Simple" 
									LayoutMode="Simple"     
									OverridesDefaultStyle="True" 
									OverlapRemovalConstraint="Must"     
									EdgeRoutingConstraint="Must"/>
           
        </zoom:ZoomControl>

Code behind:

            TryVeiwModel tryVeiw = new TryVeiwModel();
            graphLayout.DataContext = tryVeiw;
            Zoom.Mode = ZoomControlModes.Fill;

2-I'm also trying to add another wpf control inside the graph area lats say a text box,so

it will be shown as the zoom control to the left of the graph.So is that possible??

Thanks in advance

New Post: Layout Animation

c_erickson — Fri, 13 Jan 2012 17:26:51 GMT

[Accidentally double-posted]