Graph&#35;

SonoranCellist

Jun 29, 2009 at 8:06 AM

Edited Jun 29, 2009 at 10:21 AM

Hi there,

I'm really liking Graph# so far! Quick question:

How does one override the behavior of having each Vertex on a Graph, so that it doesn't display the ToString() of the object the Vertex represents, but instead uses an ItemTemplate to define the appearance of each Vertex?

Thanks! And thanks for Graph#!

palesz

Coordinator

Jun 29, 2009 at 10:39 AM

Edited Jun 29, 2009 at 10:39 AM

You can use DataTemplates for example:

<Window ...
                    xmlns:myns="clr-namespace:NamespaceOfYourVertexType[OPTIONALLY needed this: ;assembly=assembly_name_which_contains_your_vertex_class_if_its_not_the_same_as_your_window's_assemlby_(without_dll_postfix)]">
    <Window.Resources>
    <!-- define with a datatemplate how to show your vertex class-->
    <DataTemplate DataType="{x:Type myns:YourVertexType}">
        <!-- here goes my vertex representation -->
    </DataTemplate>
    </Window.Resources>

    <!-- here is the GraphLayout Control -->
</Window>

badang

Developer

Jul 1, 2009 at 8:36 AM

this is on of my implementation:

        <DataTemplate DataType="{x:Type common_graph:EntityVertex}">

            <Border Name="vertexPanel"

                    Margin="3"

                    Padding="4"

                    CornerRadius="5, 5, 5, 5"

                    BorderThickness="2"

                    BorderBrush="LightGray"

                    >

                <StackPanel ToolTip="{Binding Path=Description}">

                    <TextBlock Text="{Binding Path=Code, FallbackValue=VertexId}" TextAlignment="Center"/>                

                </StackPanel>

            </Border>

            <DataTemplate.Triggers>

                <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Factory">

                    <Setter  TargetName="vertexPanel" Property="Background" Value="LightBlue"/>

                </DataTrigger>

                <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Department">

                    <Setter  TargetName="vertexPanel" Property="Background" Value="LightGreen"/>

                </DataTrigger>

                <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="ProductionLine">

                    <Setter  TargetName="vertexPanel" Property="Background" Value="LightYellow"/>

                </DataTrigger>

                <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Workcenter">

                    <Setter  TargetName="vertexPanel" Property="Background" Value="Yellow"/>

                </DataTrigger>

                <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Workstation">

                    <Setter  TargetName="vertexPanel" Property="Background" Value="WhiteSmoke"/>

                </DataTrigger>

                <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="ProductionMachine">

                    <Setter  TargetName="vertexPanel" Property="Background" Value="NavajoWhite"/>

                </DataTrigger>

            </DataTemplate.Triggers>

        </DataTemplate>

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SonoranCellist Jun 29, 2009 at 8:06 AM Edited Jun 29, 2009 at 10:21 AM	Hi there, I'm really liking Graph# so far! Quick question: How does one override the behavior of having each Vertex on a Graph, so that it doesn't display the ToString() of the object the Vertex represents, but instead uses an ItemTemplate to define the appearance of each Vertex? Thanks! And thanks for Graph#!

palesz Coordinator Jun 29, 2009 at 10:39 AM Edited Jun 29, 2009 at 10:39 AM	You can use DataTemplates for example: <Window ... xmlns:myns="clr-namespace:NamespaceOfYourVertexType[OPTIONALLY needed this: ;assembly=assembly_name_which_contains_your_vertex_class_if_its_not_the_same_as_your_window's_assemlby_(without_dll_postfix)]"> <Window.Resources> <!-- define with a datatemplate how to show your vertex class--> <DataTemplate DataType="{x:Type myns:YourVertexType}"> <!-- here goes my vertex representation --> </DataTemplate> </Window.Resources> <!-- here is the GraphLayout Control --> </Window>

badang Developer Jul 1, 2009 at 8:36 AM	this is on of my implementation: <DataTemplate DataType="{x:Type common_graph:EntityVertex}"> <Border Name="vertexPanel" Margin="3" Padding="4" CornerRadius="5, 5, 5, 5" BorderThickness="2" BorderBrush="LightGray" > <StackPanel ToolTip="{Binding Path=Description}"> <TextBlock Text="{Binding Path=Code, FallbackValue=VertexId}" TextAlignment="Center"/> </StackPanel> </Border> <DataTemplate.Triggers> <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Factory"> <Setter TargetName="vertexPanel" Property="Background" Value="LightBlue"/> </DataTrigger> <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Department"> <Setter TargetName="vertexPanel" Property="Background" Value="LightGreen"/> </DataTrigger> <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="ProductionLine"> <Setter TargetName="vertexPanel" Property="Background" Value="LightYellow"/> </DataTrigger> <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Workcenter"> <Setter TargetName="vertexPanel" Property="Background" Value="Yellow"/> </DataTrigger> <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="Workstation"> <Setter TargetName="vertexPanel" Property="Background" Value="WhiteSmoke"/> </DataTrigger> <DataTrigger Binding="{Binding Path=EntityType.Name}" Value="ProductionMachine"> <Setter TargetName="vertexPanel" Property="Background" Value="NavajoWhite"/> </DataTrigger> </DataTemplate.Triggers> </DataTemplate>